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(F)=-(3F)^2-4
We move all terms to the left:
(F)-(-(3F)^2-4)=0
determiningTheFunctionDomain -(-3F^2-4)+F=0
We get rid of parentheses
3F^2+F+4=0
a = 3; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·3·4
Δ = -47
Delta is less than zero, so there is no solution for the equation
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